高孔洞率复合保温砌块设计及热工性能影响因素

Design of High Porosity Composite Insulation Block and Influence Factors of Its Thermal Performance

关键词:  复合保温砌块  热工性能  导热系数  孔洞率  ABAQUS

Key words:  composite insulation block  thermal performance  thermal conductivity  porosity  ABAQUS

摘要:

提出了高孔洞率复合保温砌块孔型的设计方法，同时采用ABAQUS有限元软件进行数值模拟，分析了复合保温砌块的孔型排布、孔洞率和材料导热系数对其热工性能的影响.结果表明：复合保温砌块的热阻随孔洞率的提高而增加，随实体材料导热系数的降低而增加，随填充的保温材料导热系数的降低而增加；通过数值模拟计算，得到了复合保温砌块热阻与孔洞率、实体材料导热系数、保温材料导热系数的关系公式；在灰缝对墙体传热影响很小的情况下，当砌块孔洞率为60%时，240mm厚单一砌块墙体的传热系数能达到029W/(m2·K)，满足砌块和墙体热工性能大幅提升的需求.

Abstract:

A method for designing high porosity composite insulation block was proposed. The numerical simulation of composite insulation block was carried out by using ABAQUS finite element software. The influence of pore configuration， porosity and thermal conductivity of materials on the thermal performance of the composite insulation block was studied. The results show that the thermal resistance of the composite insulation block increases with increase of porosity，decrease of thermal conductivity of the matrix material and filled thermal insulation materials. Through numerical simulation，the relation formulas between the thermal resistance of composite insulation block and porosity, thermal conductivity of the matrix materials, filled thermal insulation materials were obtained. In the case that the mortar joint has little effect on heat transfer of wall, when the porosity of the block is 60%，the heat transfer coefficient of 240mm thickness single block wall can reach 029W/(m2·K)，it can meet the demand of substantial improvement of the thermal performance of block and wall.